A frog sits on the end of a long board of length 
. The board rests on a frictionless horizontal table. The frog wants to jump to the opposite end of the board. What is minimum take off speed 
in 
relative to the ground that the frog follows to do the trick? [Assume that, the board and frog have equal masses.]
Text Solution
Verified by ExpertsC
Let the speed of the board be 
and frog jumps with angle of inclination to the board 
, then
from law of conservation of momentum in horizontal direction,
… (i)
Let distance moved by board be 
.
So, 
… ..(ii)
and 
… (iii)
Solving above equations, we get
Also, 
Hence, 
should be minimum for 
(i.e. maximum)
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